For ΔABC, ∠A = 4x + 7, ∠B = 2x + 3, and ∠C = 6x - 10. If ΔABC undergoes a dilation by a scale factor of 2 to create ΔA'B'C' with ∠A' = 5x - 8, ∠B' = 3x - 12, and ∠C' = 7x - 25, which confirms that ΔABC∼ΔA'B'C by the AA criterion?

A) ∠A = ∠A' = 47° and ∠B = ∠B' = 23°

B) ∠A = ∠A' = 47° and ∠C = ∠C' = 50°

C) ∠B = ∠B' = 33° and ∠C = ∠C' = 80°

D) ∠B = ∠B' = 23° and ∠C = ∠C' = 45°

Question

Harley George

Mathematics

27 September, 01:33

For ΔABC, ∠A = 4x + 7, ∠B = 2x + 3, and ∠C = 6x - 10. If ΔABC undergoes a dilation by a scale factor of 2 to create ΔA'B'C' with ∠A' = 5x - 8, ∠B' = 3x - 12, and ∠C' = 7x - 25, which confirms that ΔABC∼ΔA'B'C by the AA criterion?

A) ∠A = ∠A' = 47° and ∠B = ∠B' = 23°

B) ∠A = ∠A' = 47° and ∠C = ∠C' = 50°

C) ∠B = ∠B' = 33° and ∠C = ∠C' = 80°

D) ∠B = ∠B' = 23° and ∠C = ∠C' = 45°

+3

Answers (1)

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Rex Cantu · Answer 1

The correct answer for the question that is being presented above is this one: " C) ∠B = ∠B' = 33° and ∠C = ∠C' = 80°."

A triangle has a total of 180 degrees.

In order to get x:

180 = 4x + 7 + 2x + 3 + 6x - 10

180 = 12x - 0

x = 15

∠A = 4x + 7 = 67

∠B = 2x + 3 = 33

∠C = 6x - 10 = 80