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1 December, 00:40

How many solutions are there to 3x-10 (x+2) = 13-7x

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  1. 1 December, 00:41
    0
    This is the following way to solve this problem:

    3x-10 (x+2) = 13-7x

    3x-10x-20=13-7x (multiply 10 times what's in the parentheses)

    -7x-20=13-7x (subtract 3x from - 10x)

    -7x-20-13=-7x (since the 13 is positive, when we move it to the other

    side, we change it's sign, so now we subtract 13 from 20

    -7x-7=-7x

    -7=-7x+7x (we do the same thing we did above, now with the - 7x)

    -7=x

    x=-7

    Answer: x = - 7

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    :)
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