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8 February, 06:28

Tamika had a 4 by 7 in. photograph enlarged. Both length and width were increased to 130% of the original size. Find the perimeter of the enlarged photograph.

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  1. 8 February, 06:48
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    4*130%=5.2

    7*130%=9.1

    5.2*2+9.1*2=28.6 in

    or You can just do

    (4+7) * 130%*2=28.6 in
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