Lisa is using trial and improvement to find a solution to this equation:

X squared - 3X=1

What value of X should Lisa try

Not sure about that but you can factor and solve

if you have xy=0 then x or/and y=0

so x^2-3x=1

subtract 1

x^2-3x-1=0

what 2 number multiply to get - 1 and add to get - 3

the numbers are aprox 3.15831 and - 0.15831 so

(x+3.15831) (x-0.1831) = 0

set them to zero

x+3.15831=0

subtract 3.15831 from both sides

x=-3.15831

x-0.1831=0

add 0.1831 to both sides

x=0.1831

so x=0.1831 or - 3.15831