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10 October, 16:12

Find the 19th term of the arithmetic sequence whose common difference is = d5 and whose first term is = a12.

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  1. 10 October, 17:21
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    An=a1+d (n-1)

    a1=first term

    d=common difference

    n=which term

    common difference is 5 first term is 2

    an=5+2 (n-1)

    19th term is n=19

    a19=5+2 (19-1)

    a19=5+2 (18)

    a19=5+36

    a19=41

    19th term is 41
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