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6 September, 20:41

Completely factored form of xy^3 - x^3y?

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  1. 6 September, 20:53
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    xy (y - x) (y + x)

    Step-by-step explanation:

    take out a common factor xy from both terms

    = xy (y² - x²)

    y² - x² is a difference of squares and factors in general as (y - x) (y + x)

    Hence

    xy³ - x³y = xy (x - y) (x + y)
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