The leg of a right triangle is 3 units and the hypotenuse is 11 units. What is the length, in units, of the other leg of the triangle

A^2 + b^2 = c^2

3^2 + b^2 = 11^2

9 + b^2 = 121

b^2 = 121 - 9

b^2 = 112 ...

b = square root of 112

b = 10.58

Pythagorean theorem (or however it is spelled)

a^2 + b^2 = c^2 ... where a and b are the legs and c is the hypotenuse

3^2 + b^2 = 11^2

9 + b^2 = 121

b^2 = 121 - 9

b^2 = 112 ... take the square root of both sides, eliminating the ^2

b = square root of 112

b = 10.58 < = = = the other leg of the triangle