Solve system of equation y=x^2+3x+1, y=-x-3

x = - 2

y = - 1

Step-by-step explanation:

y = x² + 3x + 1 y = - x - 3

Set the equations equal to each other:

x² + 3x + 1 = - x - 3

Move all terms to one side:

x² + 3x + x + 1 + 3 = 0

x² + 4x + 4 = 0

factor:

(x + 2) ² = 0

take square root of both sidesL

x + 2 = 0

subtract 2 from both sides:

x = - 2

Plug - 2 in for x in either of the equations:

(-1) ²+3 (-1) + 1 = y

y = - 1