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24 October, 05:53

A hockey season ticket holder pays $72.48 for her tickets plus $6.00 for a program each game. A second person pays $18.08 for a ticket to every game, but doesn't buy programs. In how many games will they have paid the same amount?

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  1. 24 October, 05:55
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    If I understand the question correct, the hockey season ticket holder paid $72.48 for all of the tickets at once, and then $6.00 for each game thereafter. The second person pays $18.08 for a ticket per game.

    So then let g = the number of games. The problem can be written as a system of equations:

    Person 1 = 72.48 + 6g

    Person 2 = 18.08g

    We are looking for when the number of games for both are the same. To do this, just set them equal to each other and solve for g.

    72.48 + 6g = 18.08g

    Subtract 6g:

    72.48 = 12.08g

    Divide by 12.08:

    g = 6

    So after 6 games, the two would have paid the same price.
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