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18 July, 15:41

G use part 1 of the fundamental theorem of calculus to find the derivative of the function. sqrt (4+7t)

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  1. 18 July, 15:57
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    Let y = √4+7t

    then u = 4+7t

    y=√u = u^½

    du/dt = 7

    dy/du = ½U^-½

    dy/dt = du/dt • dy/du

    = 7*½U^-½

    = 7/2√U

    = 7 / (2{√4+7t})
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