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1 April, 19:05

What is the total mass of 222rn remaining in an original 160 milligram sample?

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  1. 1 April, 21:02
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    n x / 160 = - k x 19.1

    rate of reaction is required

    222Rn has a half-life of 3.8235 d.

    160 Ă -.5^ (19.1/3.8235) = 5.0 mg

    5.0 mg is the total mass of 222Rn remaining in an original 160-milligram sample of 222Rn.
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