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8 April, 00:11

A hula hoop has a three foot diameter how far will it travel in 6 revolution

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Answers (2)
  1. 8 April, 00:12
    0
    It will travel 56.52 ft in 6 revolution.

    Explanation:

    We know that Circumference of circle = 2πr

    where diameter is already given so by putting it in the formula we get the following result for radius (r)

    Diameter = 3 ft

    Therefore the radius r = diameter/2 = 3/2 = 1.5 ft

    So circumference of loop is:

    Circumference = 2πr = 2 * 3.14 * 1.5 = 9.42 ft

    We have to find the distance traveled in 6 revolution

    As we know that distance traveled in one revolution = 9.42 ft

    So distance traveled in 6 revolution = 6 * 9.42 = 56.52 ft
  2. 8 April, 00:31
    0
    Distance traveled in 6 revolution = 56.52 ft

    Step-by-step explanation:

    Formula:

    Circumference of circle = 2πr

    r - Radius of circle

    It is given that,

    A hula hoop has a three foot diameter.

    Diameter = 3 ft

    Therefore the radius r = diameter/2 = 3/2 = 1.5 ft

    To find the circumference of loop

    r = 1.5 ft

    Circumference = 2πr = 2 * 3.14 * 1.5 = 9.42 ft

    To find the distance traveled in 6 revolution

    Distance traveled in one revolution = 9.42 ft

    Distance traveled in 6 revolution = 6 * 9.42 = 56.52 ft
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