An object is thrown upward from the top of a 112 foot building with an initial velocity of 96 feet per second. The height h of the object after t seconds is given by the quadratic equation h=-16t + 96t + 112. When will the object hit the ground?

Question

Kathryn Irwin

Mathematics

26 January, 13:57

An object is thrown upward from the top of a 112 foot building with an initial velocity of 96 feet per second. The height h of the object after t seconds is given by the quadratic equation h=-16t + 96t + 112. When will the object hit the ground?

+1

Answers (1)

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Julian Bauer · Answer 1

h = - 16t²+96t+112

=> - 16t²+96t+112 = 0

divide both sides by - 16

=> t²-6t-7=0

=> t²+t - 7t-7=0

=> t (t + 1) - 7 (t + 1) = 0

=> (t + 1) (t - 7) = 0

=> t = - 1 or 7

=> The object will hit the ground after 7 seconds.

(because - 1 seconds makes no sense)