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Deanna Osborne
Mathematics
22 September, 13:12
Tan A (secA-cosA) / sinA
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Schaefer
22 September, 13:15
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tan A (secA-cosA) / sinA = tan²A
Step-by-step explanation:
tanA (secA - cosA) / sinA = (SinA / CosA) (secA - cosA) / sinA
= (1 / CosA) (1 / CosA - CosA) = 1 / Cos²A - 1 = (1 - Cos²A) / Cos²A
= sin²A / Cos²A
= tan²A
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