Rewrite the expression by factoring (y+7) 3y (y+7) + (y+7)

(3y+2) (y+7)

Step-by-step explanation:

I think you meant (y+7) + 3y (y+7) + (y+7). Anyways, we have to count the number of (y+7) there are. The first term tells us we have 1 group. The second term tell us we have 3y groups. The last term tells us we have 1 group. Therefore we have 1+3y+1 groups of y+7 which gives us (3y+2) (y+7)

(3y+2) (y+7). There you go