Ask Question
3 March, 04:54

The sum of the digits of a certain two-digit number is 9. When you reverse its digits you increase the number by 63. What is the number?

+1
Answers (1)
  1. 3 March, 05:03
    0
    The given such number is 18.

    Step-by-step explanation:

    Here, sum of the two digits is 9

    Let us assume the tens digit = m

    So, the unit's digit of the number = 9 - m

    Now, the current value of the number = 10 (Tens Digit) + 1 (units digit)

    = 10 (m) + 1 (9-m) = 10 m + 9 - m = 9 m + 9 ... (a)

    Second Case:

    Here after reversing the digits, the ten's digit = 9 - m

    The unit's digit = m

    So, the new value of the number = 10 (Tens digit) + 1 (Unit Digit)

    = 10 (9 - m) + m = 90 - 10 m + m = 90 - 9 m ... (b)

    Now, according to the question:

    The initial Number value + 63 = The new number value

    or, 9 m + 9 + 63 = 90 - 9 m

    or, 18 m = 99 - 72 = 18

    or, m = 18/18 = 1

    or, m = 1

    Hence the tens digit of the number = m = 1

    Also, the ones digit = 9 - 1 = 9 - 1 = 8

    So, the given number is 18
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The sum of the digits of a certain two-digit number is 9. When you reverse its digits you increase the number by 63. What is the number? ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers