The area of a rectangular field is x^2-x-72 m^2. The length of the field is x+8 cm. What is the width of the field meters.

Hello,

A (x) = x²-x-72 (m²)

L = (x+8) (cm) = (x+8) / 100 (m)

We suppose here x≠-8

(in reality x²-x-72>0 = = >x9

but x+8>0 = = > x>-8

then

only x>9 are solutions)

W=A (x) / ((x+8) / 100) = 100 * (x²-x-72) / (x+8) = 100 * (x-9) (x+8) / (x+8) = 100 * (x-9)