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Tabby
Mathematics
30 June, 07:05
2w (3w-1) = 6w-2w = 4w
is this correct?
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Carlos
30 June, 07:07
0
No, sorry, that's not correct.
2w (3w - 1)
We dstribute the 2w factor
= (2w) (3w) - 2w (1)
then we multiply out each term,
= 6w² - 2w
and we can stop here.
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Salma Hill
30 June, 07:29
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No
it's 6w (squared) - 2w
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