Ask Question
8 August, 12:03

An online presented this question "Would the recent norovirus outbreak deter you from takind a cruise?". Among the 34,271 people who responded, 62% answered "Yes". Use the sample data to construct a 95% confidence interval estimate for the proportion of the population of all the people who would respond yes to that question. Does the confidence interval provide a good estimate of the population proportion?

+1
Answers (1)
  1. 8 August, 12:32
    0
    95% C. I. = 0.62 + or - 1.96 * sqrt[0.62 (1 - 0.62) / 34,271] = 0.62 + or - sqrt (6.875 x 10^-6) = 0.62 + or - 0.002622 = 0.62 - 0.002622 to 0.62 + 0.002622 = 0.6174 to 0.6226 = 61.74% to 62.26%.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An online presented this question "Would the recent norovirus outbreak deter you from takind a cruise?". Among the 34,271 people who ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers