Y=25x+35

Describe what this graph would look like. Where would it start? How would the slope be counted out?

Question

Kolton Freeman

Mathematics

21 October, 11:28

Y=25x+35

Describe what this graph would look like. Where would it start? How would the slope be counted out?

+5

Answers (2)

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Giuliana Salazar · Answer 1

Y = mx + b

M is slope. b is y-intercept

The graph would start at 35 (y-int)

The slope would be counted as 25/1 ... aka, 25 up, 1 right.

Ada Burton · Answer 2

The equation is in the form y=mx+b, where m=slope, b=y-intercept.

The y-intercept is 35: so the line goes through the y-axis at (0,35).

The slope is 25: so we need to count out the slope as rise over run, or 25 up and 1 to the right, starting from the y-intercept.

Y=25x+35Describe what this graph would look like. Where would it start? How would the slope be counted out?

Y=25x+35

Describe what this graph would look like. Where would it start? How would the slope be counted out?