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7 December, 12:18

The sum of three consecutive even integers is 30 more than the smallest integer

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  1. 7 December, 12:44
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    Let's call the smallest of the three even integers ' T ' (for 'tiny')

    The second even number is T + 2.

    The third even number is T + 4.

    Add up the 3 even numbers: T + (T + 2) + (T + 4) = 3T + 6

    This is 30 more than the smallest of the three.

    3T + 6 = T + 30

    Subtract T from each side: 2T + 6 = 30

    Subtract 6 from each side: 2T = 24

    Divide each side by 2 : T = 12

    The three consecutive even integers are 12, 14, and 16.

    Check: 12 + 14 + 16 = 42. By George, that's 30 more than 12!
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