A committee of three people is to be chosen from four married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot both serve on the committee?

A. 16

B. 24

C. 26

D. 30

E. 32

total selections = 56

let's say that couple is always present in this committee of three.

This means that there are 4 ways to select 2 people of the committee. (4 couples and any one couple can be selected in 4 ways)

The third person can be selected out of remaining 6 people in 6 ways.

Therefore when couple exists there are: 4X6 = 24 ways

Thus no couple = (4X6) = 32