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5 July, 03:06

The width of a rectangle is 18 in less than its length. if the area of the rectangle is 1440 in^2, find the dimensions of the rectangle

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  1. 5 July, 03:24
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    Length: L

    width: L - 18

    Area (A) = L x w

    1440 = L (L - 18)

    1440 = L² - 18L

    0 = L² - 18L - 1440

    0 = (L + 30) (L - 48)

    0 = (L + 30) 0 = (L - 48)

    L = - 30 L = 48

    Since length cannot be negative, disregard - 30

    L = 48

    width: L - 18 = 48 - 18 = 30

    Answer: width=30 in, length=48 in
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