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Maximus Nielsen
Mathematics
27 January, 14:55
How do you solve 9^x=3^40?
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Dominick Lamb
27 January, 15:20
0
Answer: x = 20
Step-by-step explanation:
Manipulate the bases so they are the same, then set the exponents equal to each other and solve for x:
9ˣ = 3⁴⁰
(3²) ˣ = 3⁴⁰
3²ˣ = 3⁴⁰
2x = 40
x = 20
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Baby Doll
27 January, 15:24
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We have 9 = 3^2;
Then, 9^x = (3^2) ^x = 3^ (2x);
We solve 3^ (2x) = 3^40;
2x = 40;
x = 20 : 2;
x = 10;
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