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30 June, 08:46

Using elimination method, simultaneously solve this equation: 2y+3x=7 and 4x+3y=15

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  1. 30 June, 09:13
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    Answer: x = - 9, y = 14

    Step-by-step explanation:

    3x + 2y = 7 ... equation 1

    4x + 3y = 15 ... equation 2

    Solving using elimination method, we have to decide the variable we are eliminating first, we could eliminate x or y. If we are to eliminate y first, we will multiply equation 1 by 3 and equation 2 by 2 so that the coefficient of y can be the same. The equation then becomes

    3 (3x + 2y = 7)

    2 (4x + 3y = 15)

    Expanding, we have

    9x + 6y = 21 ... equation 3

    8x + 6y = 30 ... equation 4

    Now that the coefficient of y is the same, we will subtract equation 4 from equation 3 to eliminate y, we have

    x = - 9

    Substitute y = - 9 into equation 1 to find the value of x, we have:

    3 (-9) + 2y = 7

    -27 + 2y = 7

    2y = 7 + 27

    2y = 34

    y = 34/2

    y = 14
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