a. Leena consumed 1,500 calories at dinner.

b. The equation 2/3 (x + 400 + 350) = x can be used to model the situation.

c. Leena consumed 500 calories at dinner.

d. The equation 2/3 (x) = x (400 + 300) can be used to model the situation.

e. Leena consumed 1,000 calories at dinner.

f. The equation 2/3x (400 + 300) = x can be used to model the situation.

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