The coach of a softball team is holding tryouts and can take only 2 more players for the team. there are players 8 trying out. how many different groups of 2 players could possibly be chosen?

Question

Barrett Newman

Mathematics

16 April, 01:05

The coach of a softball team is holding tryouts and can take only 2 more players for the team. there are players 8 trying out. how many different groups of 2 players could possibly be chosen?

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Nora Sanders · Answer 1

The order in which the two players will be selected from the 8 trying players is not important. The most important thing is to have the two players.

Therefore, this is a question of combination.

The number of groups = 8C2 = 8!/[2! * (8-2) !] = (8*7*6*5*4*3*2*1) / [ (2*1) * (6*5*4*3*2*1) ] = 28 groups