Write the expression, log 3x - 2 logx - log (2+y) ], as a single logarithm.

Answer: log (3 / x[2+y])

Step-by-step explanation:

Hi to answer this question we have to follow the next steps:

log 3x - 2 logx - log (2+y) ]

Simplify the second term

log 3x - logx² - log (2+y) ]

Use the quotient property of logarithms in the first 2 terms

log (3x / x²) - log (2+y)

log (3 / x) - log (2+y)

Use the quotient property of logarithms again

log (3/x : [2+y])

Combine

log (3 / x [2+y])