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16 August, 16:58

Find two consecutive even integers such that eight times the first equals seven times the second equals

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  1. 16 August, 17:17
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    Hence two consecutive even integers are 14 and 16

    Step-by-step explanation:

    Let x and x+2 be the two consecutive even integers

    Then according to the given statement in the question

    8x = 7 (x+2)

    Distributive property

    8x=7x+14

    Subtraction Property of Equality

    8x-7x = 14+7x-7x

    Simplifying

    x = 14

    So the first integer is 14 and second is:

    x+2 = 14+2 = 16

    Hence two consecutive even integers are 14 and 16 ...
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