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23 March, 20:15

You have 9 chairs arranged in a circle, and wish to seat 9 people (one person per seat). The one constraint is that person A cannot sit next to person B or person C (three of the people). How many ways are there to seat them?

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  1. 23 March, 20:43
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    30240 number of ways are there to seat them

    Step-by-step explanation:

    Total number of ways of arranging 9 people on 9 chairs in circular manners = (9-1) ! = 8! =

    number of ways A sit always sit next to B = AB together makes a single and

    therefore total number of arrangements for this = 7 + (AB) = 8 that is 8 persons sitting in circular manner

    number of ways = (8-1) ! = 7! = 5040

    likewise number of arrangements for A and C will be = 5040

    Total number of ways such that A cannot sit next to B or C = total ways of 9 persons - total number of A always sitting next to B - total number of ways always sitting next to C = 8! - 7!-7!

    = 40320 - 5040-5040

    = 30240

    =
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