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6 December, 11:13

What is the radius of the circle with this equation of (x-5) 2 + (y+7) 2=8

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  1. 6 December, 11:29
    0
    2√2

    Step-by-step explanation:

    compare this equation with the standard equation of a circle centered at (h, k) with radius r:

    (x - h) ^2 + (y - k) ^2 = r^2

    (x - 5) ^2 + (y + 7) ^2=8

    Clearly, r^2 = (radius) ^2 = 8, and so the radius, r, is √8, or 2√2
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