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9 September, 07:12

One number is 2 less than a second number. twice the second number is 2 less than 3 times the first. Find the two numbers

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  1. 9 September, 07:26
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    Answer: 6 and 8

    Step-by-step explanation: Call the first number x and the second number y.

    One number is two less than the second number so x=y-2 (*)

    Twice the second number is 2 less than 3 times the first gives us,

    2y=3x-2

    Substituting equation (*) into this equation gives,

    2y=3 (y-2) - 2 which solves to give y=8 and (*) gives x=6
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