The speed of a moving sidewalk at an airport is 6 ft/sec. a person can walk 51 ft forward on the moving sidewalk in the same time it takes to walk 7 ft on a nonmoving sidewalk in the opposite direction. At what rate wools a person walk on a moving sidewalk?

Question

Hope Davila

Mathematics

16 March, 22:06

The speed of a moving sidewalk at an airport is 6 ft/sec. a person can walk 51 ft forward on the moving sidewalk in the same time it takes to walk 7 ft on a nonmoving sidewalk in the opposite direction. At what rate wools a person walk on a moving sidewalk?

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Answers (1)

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Craig Hansen · Answer 1

Distance = rate*time

Let v be speed of person walking.

6t + vt = 51

vt = 7

Solve for t:

6t + 7 = 51

t = 44/6 = 22/3

Sub in to find v:

v (22/3) = 7

v = 21/22

The speed a person walks is 21/22 ft/sec