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26 April, 05:34

A bag contains 6 red marbles, 2 blue marbles, and 1 green marble. What is the

probability of choosing 2 marbles that are not green when 2 marbles are drawn

from the bag? (no replacement before choosing second marble)

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Answers (1)
  1. 26 April, 05:49
    0
    We have 1 green and 8 non-green.

    We get a probability of 8/9 of a non-green for the first marble and a probably of 7/8 for the second being non green, so

    p = (8/9) * (7/8) = 7/9

    Answer: 7/9
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