Given:, and. Prove: ∠PCQ is complementary to ∠ABC. Proof: Since, m∠OCQ = 90° by the definition of perpendicular lines. By angle addition, we can say m∠OCQ = m∠OCP + m∠PCQ. But since m∠OCQ = 90°, m∠OCP + m∠PCQ = 90° by the Transitive Property of Equality. [Missing Step] By the definition of congruent angles, m∠OCP = m∠ABC. This leads to m∠ABC + m∠PCQ = 90° by the Transitive Property of Equality. So, based on the definition of complementary angles, ∠PCQ is complementary to ∠ABC. What is the missing step

Question

Karsyn Daniel

Mathematics

27 November, 13:04

Given:, and. Prove: ∠PCQ is complementary to ∠ABC. Proof: Since, m∠OCQ = 90° by the definition of perpendicular lines. By angle addition, we can say m∠OCQ = m∠OCP + m∠PCQ. But since m∠OCQ = 90°, m∠OCP + m∠PCQ = 90° by the Transitive Property of Equality. [Missing Step] By the definition of congruent angles, m∠OCP = m∠ABC. This leads to m∠ABC + m∠PCQ = 90° by the Transitive Property of Equality. So, based on the definition of complementary angles, ∠PCQ is complementary to ∠ABC. What is the missing step

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Neil Wilkins · Answer 1

the [Missing Step]

according to the figure, ∠OCP and ∠ABC are congruent, these angles are called corresponding angles. By the definition of congruent angles, m∠OCP = m∠ABC