What is the standard form of a line with the x intercept of 4 and y intercept of - 2?

x-2y=4

Step-by-step explanation:

So from the question we know the following:

When something is x intercept it means y=0 so we have (4,0)

When something is y intercept it means x=0 so we have (0,-2)

Now you use these to find the slope using the formula m = (y2-y1) / (x2-x1)

Plug in the values

m = (-2-0) / 0-4)

m = (-2/-4)

m = 1/2

x-2y=4

Now you just plug this in slope intercept form y=mx+c, where c is y intercept

y=1/2 x - 2

Standard form: ax+by=c

y=1/2 x - 2 (rearrange to match the above equation)

-1/2 x + y = -2 (multiply both sides by 2 because we can't have a fraction for a in the standard form)

-1x+2y=-4 (now multiply both sides by - 1 because a cannot be negative)

x-2y=4