Ask Question
4 November, 18:56

The height h (in feet) of an object thrown vertically upward from a tower 144 feet tall is given by h=144+128t-16t², where t measures the time in seconds from the time when the object is released. how long does it take for the object to reach the ground?

+5
Answers (1)
  1. 4 November, 19:05
    0
    It takes 9 seconds to hit the ground.

    Setting the equation equal to 0, we have:

    0 = 144 + 128t - 16t²

    Factoring out the GCF, we have

    0 = 16 (9 + 8t - t²)

    Factoring out - 1, we have:

    0 = - 16 (-9 - 8t + t²)

    In standard form, this is

    -16 (t² - 8t - 9) = 0

    This is easily factorable; - 9 (1) = - 9 and - 9+1 = - 8:

    -16 (t-9) (t+1) = 0

    Using the zero product property, we know either t-9=0 or t+1=0; therefore t=9 or t=-1. Since negative time makes no sense, t=9.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The height h (in feet) of an object thrown vertically upward from a tower 144 feet tall is given by h=144+128t-16t², where t measures the ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers