A lawyer owns 4 pairs of pants, 5 dress shirts and 6 ties. How many days can the lawyer go without wearing the same combination of three items?

I believe that to calculate this, you do 4x5x6 and then divide it by 3, to get 40

4 ways to wear all pants

5 ways to wear shirts

6 ways to wear ties

4*5*6=120 different combos

think of it like this

eample

2 pairs of pants and 3 pairs of shirts

a, b are the pants, and c, d, e are the shirts

the ways are below

ac

ad

ae

bc

bd

be

2*3=6, 6 ways

answer is 120 days