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11 March, 10:01

P Casey is reading a book for a book report. At 3:30 P. M., he started reading where he had left off the day before. At 5:30 P. M. he was on page 160. At 8:00 P. M. he was on page 280. If reading the book is modeled by a linear function, what page did Casey start on at 3:30 P. M.?

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  1. 11 March, 10:19
    0
    Given:

    3:30 - 5:30 = page 160

    5:30 - 8:00 = page 280

    280 - 160 = 120

    8:00 - 5:30 = 2.5 hours or 5 half hours

    120 / 5 half hours = 24 pages every half hour or 30 minutes

    3:30 - 5:30 = 2 hours or 4 half hours

    24 * 4 = 96 pages

    160 - 96 = 64

    P Casey was on page 64 at 3:30 p. m.
  2. 11 March, 10:22
    0
    If you would like to know the page that Casey start on at 3:30 P. M., you can calculate this using the following steps:

    8:00 P. M. - 5:30 P. M. = 2:30

    280 - 160 = 120 pages

    5:30 P. M. - 3:30 P. M. = 2:00

    2:30 = 150 minutes ... 120 pages

    2:00 = 120 minutes ... x pages = ?

    150 * x = 120 * 120

    x = 120 * 120 / 150

    x = 96 pages

    160 pages - 96 pages = 64

    Casey started on page 64.
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