What is the domain of the square root function graphed below? On a coordinate plane, a curve open up to the right in quadrant 4. It starts at (0, negative 1) and goes through (1, negative 2) and (4, negative 3).

Question

Ashlynn Ryan

Mathematics

12 June, 16:10

What is the domain of the square root function graphed below? On a coordinate plane, a curve open up to the right in quadrant 4. It starts at (0, negative 1) and goes through (1, negative 2) and (4, negative 3).

+2

Answers (2)

Know the Answer?

Kianna Owens · Answer 1

Answer: x ≥ 0

Step-by-step explanation:

just did this

Melvin Pitts · Answer 2

x ≥ 0

Step-by-step explanation: Domain means the x-value. The graph starts at (0, - 1) and then moves right and down. Because the question is asking for the domain, the coordinate you should be looking for is the x coordinate. Find where the x-coordinate begins or ends. It begins at 0 and never goes towards the negative area, however it does go positive for infinite. Lastly, because the line of the graph is a solid hole and not an empty one, 0 is included as an answer. Therefore the domain must be greater or equal to 0.