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21 June, 00:20

How do you solve X/2-5=10

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  1. 21 June, 00:45
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    Answer: x2-5=10

    Two solutions were found:

    x = ± √15 = ± 3.8730

    Reformatting the input:

    Changes made to your input should not affect the solution:

    (1) : "x2" was replaced by "x^2".

    Rearrange:

    Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation:

    x^2-5 - (10) = 0

    Step by step solution:

    Step 1:

    Trying to factor as a Difference of Squares:

    1.1 Factoring: x2-15

    Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

    Proof : (A+B) • (A-B) =

    A2 - AB + BA - B2 =

    A2 - AB + AB - B2 =

    A2 - B2

    Note : AB = BA is the commutative property of multiplication.

    Note : - AB + AB equals zero and is therefore eliminated from the expression.

    Check : 15 is not a square!

    Ruling : Binomial can not be factored as the difference of two perfect squares.

    Equation at the end of step 1:

    x2 - 15 = 0

    Step 2:

    Solving a Single Variable Equation:

    2.1 Solve : x2-15 = 0

    Add 15 to both sides of the equation:

    x2 = 15

    When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:

    x = ± √ 15

    The equation has two real solutions

    These solutions are x = ± √15 = ± 3.8730

    Two solutions were found:

    x = ± √15 = ± 3.8730
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