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Liberty Newman
Mathematics
21 June, 00:20
How do you solve X/2-5=10
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Payton Rivers
21 June, 00:45
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Answer: x2-5=10
Two solutions were found:
x = ± √15 = ± 3.8730
Reformatting the input:
Changes made to your input should not affect the solution:
(1) : "x2" was replaced by "x^2".
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation:
x^2-5 - (10) = 0
Step by step solution:
Step 1:
Trying to factor as a Difference of Squares:
1.1 Factoring: x2-15
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 15 is not a square!
Ruling : Binomial can not be factored as the difference of two perfect squares.
Equation at the end of step 1:
x2 - 15 = 0
Step 2:
Solving a Single Variable Equation:
2.1 Solve : x2-15 = 0
Add 15 to both sides of the equation:
x2 = 15
When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:
x = ± √ 15
The equation has two real solutions
These solutions are x = ± √15 = ± 3.8730
Two solutions were found:
x = ± √15 = ± 3.8730
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