A lot of 119 semiconductor chips contains 28 that are defective. Round your answers to four decimal places (e. g. 98.7654). a) Two are selected, at random, without replacement, from the lot. Determine the probability that the second chip selected is defective.

Question

Rayne Clayton

Mathematics

14 January, 08:37

A lot of 119 semiconductor chips contains 28 that are defective. Round your answers to four decimal places (e. g. 98.7654). a) Two are selected, at random, without replacement, from the lot. Determine the probability that the second chip selected is defective.

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Answers (1)

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Dorian Vaughan · Answer 1

0.2288

Step-by-step explanation:

This is straightforward.

What we need to do is to divide the number of defective semiconductor chips over the total number of semiconductor chips.

Initially, the total number of semi conductor chips is 119 and the total number of defective semiconductor chips is 28.

After the first selections, we can infer that the total number of semiconductor chips is 118 while the number of defective ones is 27.

Hence on the second drawing, the probability that he will

Select a defective one is 27/118