The zeroes of the function are.

On a coordinate plane, a cubic function increases into quadrant 3 and 2 and then curves down into quadrant 4 before increasing into quadrant 1. It crosses the x-axis at (negative 2, 0), (0, 0), and (4, 0).

Question

Adalyn

Mathematics

11 February, 18:13

The zeroes of the function are.

On a coordinate plane, a cubic function increases into quadrant 3 and 2 and then curves down into quadrant 4 before increasing into quadrant 1. It crosses the x-axis at (negative 2, 0), (0, 0), and (4, 0).

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Answers (1)

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Zack Friedman · Answer 1

y = x (x+2) (x-4), so the zeroes are - 2, 0 and 4.

Step-by-step explanation:

y = x (x+2) (x-4)

The factors of a cubic function are (x-a), (x-b), and (x-c), where a, b, and, c are the x-intercepts. Because there are 3 intercepts, all of the "x-n"s are to the power of 1. You gave the intercepts as (-2,0), (0,0), and (4,0). From there I wrote the equation. The function I wrote increases from Q3 to Q2, then goes to Q4 to Q1. If it didn't, then I would have made the equation negative.

The zeroes of the function are.On a coordinate plane, a cubic function increases into quadrant 3 and 2 and then curves down into quadrant 4 before increasing into quadrant 1. It crosses the x-axis at (negative 2, 0), (0, 0), and (4, 0).

The zeroes of the function are.

On a coordinate plane, a cubic function increases into quadrant 3 and 2 and then curves down into quadrant 4 before increasing into quadrant 1. It crosses the x-axis at (negative 2, 0), (0, 0), and (4, 0).