Ask Question
13 June, 08:19

Find the value of k such that the system of equations does not have a solution:

10x+4y=-3

-15x+ky=14

+4
Answers (1)
  1. 13 June, 08:23
    0
    k = - 6.

    Step-by-step explanation:

    We need to make the left side of the second equation a multiple of the left side of the first one.

    We can do this by making k = - 6 (because - 15/10 = - 6/4).

    The second equation becomes

    -15x - 6y = 14

    Now multiply this by - 2/3. We get

    10x + 4y = - 28/3

    but the first equation is 10x + 4y = - 3.

    So there are no solutions.

    So the answer is k = - 6.

    ,
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Find the value of k such that the system of equations does not have a solution: 10x+4y=-3 -15x+ky=14 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers