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11 July, 13:10

If f (x) = 5x-1, then f^-1 (x) =

+5
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  1. 11 July, 13:25
    0
    f^-1 (x) = (x+1) / 5

    Step-by-step explanation:

    f (x) = 5x-1

    y = 5x-1

    Exchange x and y

    x = 5y-1

    Solve for y

    Add 1 to each side

    x+1 = 5y-1+1

    x+1 = 5y

    Divide by 5

    (x+1) / 5 = 5y/5

    (x+1) / 5 = y

    The inverse is (x+1) / 5

    f^-1 (x) = (x+1) / 5
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