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Find the common ratio in a geometric sequence where the first term is 2/5 and the third term is 1/10

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  1. 9 May, 08:15
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    GP is given by = arⁿ⁻¹

    First term of GP = 2/5, a = 2/5 ... (i)

    Third term = 1/10, ar² = 1/10 ... (ii)

    (ii) : (i)

    ar² : a = (1/10) : (2/5)

    r² = 1/10 * 5/2

    r² = 1/4 Take square root of both sides

    r = √ (1/4)

    r = 1/2.

    Common ratio = 1/2.
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