A bag contains 6 clear marbles and 4 red marbles. One marble is drawn from the bag and replaced. A second marble is drawn from the bag and replaced. What is the probability of getting a red marble the first time AND a red marble the second time?

4/25

1/4

1/5

4/5

Question

Neveah Arroyo

Mathematics

28 August, 19:22

A bag contains 6 clear marbles and 4 red marbles. One marble is drawn from the bag and replaced. A second marble is drawn from the bag and replaced. What is the probability of getting a red marble the first time AND a red marble the second time?

4/25

1/4

1/5

4/5

+4

Answers (1)

Know the Answer?

Kate Lester · Answer 1

The answer is "4/25".

bag contains 6 clear marbles and 4 red marbles = 6+4=10

chance of red marble = 4/10

4/10=2/5

Now, probability of getting a red marble the first time AND a red marble the second time = (2/5) x (2/5) = 4/25

A bag contains 6 clear marbles and 4 red marbles. One marble is drawn from the bag and replaced. A second marble is drawn from the bag and replaced. What is the probability of getting a red marble the first time AND a red marble the second time?4/251/41/54/5

A bag contains 6 clear marbles and 4 red marbles. One marble is drawn from the bag and replaced. A second marble is drawn from the bag and replaced. What is the probability of getting a red marble the first time AND a red marble the second time?

4/25

1/4

1/5

4/5