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6 August, 12:22

Without solving the equation, determine the nature of the roots of x^2 - 2x - 8 = 0.

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  1. 6 August, 12:28
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    Hello

    x²-2x-8=0

    (x²-2x+1) - 1-8=0

    (x-1) ² - 3² = 0

    (x-1+3) (x-1-3) = 0

    (x+2) (x-4) = 0

    x+2=0 or x-4=0

    x=-2 or x=4

    the roots in Z
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