A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other words, the tank is not standing vertically on one of its flat ends.) If the radius of the cylinder is 2 meters, its length is 6 meters, and its top is 4 meters under the ground, find the total amount of work needed to pump the gasoline out of the tank. (The density of gasoline is 673 kilograms per cubic meter; use g

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A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other words, the tank is not standing vertically on one of its flat ends.) If the radius of the cylinder is 2 meters, its length is 6 meters, and its top is 4 meters under the ground, find the total amount of work needed to pump the gasoline out of the tank. (The density of gasoline is 673 kilograms per cubic meter; use g=9.8m/s^2

Answer:

Work = 2,238,031 Joules

Step-by-step explanation:

Assuming the tank is initially full, and work is needed to be done to make it empty, and get the fuel to the ground level.

The tank center line is the center of gravity of the fuel, and its distance below ground level is 4 + 0.5 m m = 4.5 m.

Fuel mass = π * (2) ²*6*673 = 3.142*6*673 = 50,749 Kg

Work = weight*height

= mass*acceleration due to gravity, g*height

=50,749*9.8*4.5 = 2,238,030.9

Work = 2,238,031 Joules