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Elizabeth
Mathematics
29 December, 01:39
Solve the system of equations 3y+2z=12 and y-z=9
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Frau Frau
29 December, 01:49
0
Mulitply second equation by 2 and add to first
3y+2z=12
2y-2z=18 +
5y+0z=30
5y=30
divide 5
y=6
sub back
y-z=9
6-z=9
minus 6
-z=3
times - 1
z=--3
x=-3
y=6
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